The lowestOneBit() method of Integer class, returns an int value with a single one bit in the position of the lowest order. This is determined by placing one-bit at the lowest order (right most) in the binary representation of a given int number.
For example: If the binary representation of a given number is 0000 0000 0000 0111, then this method returns the int number equivalent to 0000 0000 0000 0001. If the given number is zero, then it returns zero.
Hierarchy:
java.lang Package
-> Integer Class
-> lowestOneBit() Method
Syntax of lowestOneBit() method
public static int lowestOneBit(int i)
lowestOneBit() Parameters
i– An int value whose lowest one bit integer number is to be determined.
lowestOneBit() Return Value
- An int value with a single one-bit, placed in the position of lowest order(rightmost) one bit.
- Returns zero, if the given number is zero.
Example 1
public class JavaExample {
public static void main(String[] args) {
// 10 binary: 1010
// lowest one bit: 0010, equivalent to decimal value 2
int i = 10;
System.out.println(Integer.lowestOneBit(i));
// 24 binary: 11000
// lowest one bit: 01000, equivalent to decimal value 8
int i2 = 24;
System.out.println(Integer.lowestOneBit(i2));
}
}
Output:
Example 2
public class JavaExample {
public static void main(String[] args) {
//binary equivalent: 0100 0001 1010
//lowest one bit: 0000 0000 0010
//which is equivalent to 2
int i = -1050;
System.out.println(Integer.lowestOneBit(i));
}
}
Output:
Example 3
public class JavaExample {
public static void main(String[] args) {
int i = Integer.MAX_VALUE;
int i2 = Integer.MIN_VALUE;
System.out.println(Integer.lowestOneBit(i));
//Integer.MIN_VALUE lowest one bit
// is equal to number itself
System.out.println(Integer.lowestOneBit(i2));
System.out.println(Integer.MIN_VALUE);
}
}
Output:
