Java Math.sinh() method returns hyperbolic sine of the given value. This method accepts double type value as an argument and returns the hyperbolic sine of this value as a result. Hyperbolic sine of a value x
is defined as (ex – e-x)/2, where e is the Euler’s number whose value is 2.718281828459045.
public class JavaExample { public static void main(String[] args) { double a = 1; System.out.println(Math.sinh(a)); } }
Output:
1.1752011936438014
Syntax of Math.sinh() method
Math.sinh(90); //returns 6.102016471589204E38
sinh() Description
public static double sinh(double a): It returns hyperbolic sine of the given value(argument) a
.
sinh() Parameters
- a: A double value whose hyperbolic sine is to be determined.
sinh() Return Value
- Returns hyperbolic sine of argument
a
. - If the argument is NaN (Not a number), then it returns NaN.
- If the argument is infinity, then it returns infinity with the same sign.
- If the argument is zero, then it returns zero with the same sign.
Example 1
public class JavaExample { public static void main(String[] args) { double a1 = 1.0; double a2 = 0; double a3 = -1.0; //hyperbolic sine of different double values. System.out.println(Math.sinh(a1)); System.out.println(Math.sinh(a2)); System.out.println(Math.sinh(a3)); } }
Output:

Example 2
public class JavaExample { public static void main(String[] args) { double a1 = Double.MAX_VALUE; double a2 = Double.MIN_VALUE; double a3 = 0.0/0; //NaN System.out.println(Math.sinh(a1)); System.out.println(Math.sinh(a2)); System.out.println(Math.sinh(a3)); } }
Output:

Example 3
public class JavaExample { public static void main(String[] args) { double a1 = Double.POSITIVE_INFINITY; double a2 = Double.NEGATIVE_INFINITY; double a3 = Math.PI; System.out.println(Math.sinh(a1)); System.out.println(Math.sinh(a2)); System.out.println(Math.sinh(a3)); } }
Output:
