C program to calculate and print the value of nCr

In the following program we are calculating and displaying the value of nCr. nCr can also be represented as C(n,r)
The formula is:
C(n,r) = n! / ( r!(n – r)! ). For 0 <= r <= n. Here ! represents factorial. For example: C(6, 2) = 6! / (2! * (6-2)!) => 720/(2 * 24) => 15
The same calculation we have done in the following program.

#include <stdio.h>
 
int fact(int num);
 
void main()
{
    int n, r, ncr_var;
 
    printf("Enter the value of n:");
    scanf("%d", &n);
    printf("\nEnter the value of r:");
    scanf("%d", &r);
    /* ncr is also represented as C(n,r), the formula is:
     * C(n,r) = n! / ( r!(n - r)! ). For 0 <= r <= n.
     */
    ncr_var = fact(n) / (fact(r) * fact(n - r));
    printf("\nThe value of C(%d,%d) is: %d",n,r,ncr_var);
}
/* This function is used to find the 
 * factorial of given number num
 */
int fact(int num)
{
    int k = 1, i;
    // factorial of 0 is 1
    if (num == 0)
    {
        return(k);
    }
    else
    {
        for (i = 1; i <= num; i++)
    {
            k = k * i;
	}
    }
    return(k);
}

Output:

Enter the value of n:
5 
Enter the value of r:
2
The value of C(6,2) is: 15