C program to calculate and print the value of nPr

In the following program we are calculating the value of nPr based on the given values of n and r. nPr can also be represented as P(n,r). The formula of P(n, r) is: n! / (n – r)!. For example P(6, 2) = 6! / (6-2)! => 720 / 24 = 30. We have implemented the same logic in the below C program.

#include <stdio.h>
 
void main()
{
    int n, r, npr_var;
 
    printf("Enter the value of n:");
    scanf("%d", &n);
    printf("\nEnter the value of r:");
    scanf("%d", &r);
    
    /* nPr is also known as P(n,r), the formula is:
     * P(n,r) = n! / (n - r)! For 0 <= r <= n.
     */
    npr_var = fact(n) / fact(n - r);
    printf("\nThe value of P(%d,%d) is: %d",n,r,npr_var);
}
// Function for calculating factorial
int fact(int num)
{
    int k = 1, i;
    // factorial of 0 is 1
    if (num == 0)
    {
        return(k);
    }
    else
    {
        for (i = 1; i <= num; i++)
    {
            k = k * i;
	}
    }
    return(k);
}

Output:

Enter the value of n:
5 
Enter the value of r:
2
The value of P(6,2) is: 30