In this tutorial, we will write a **java program to find the frequency of each element in the array**.

For example, if an array is `{2, 2, 3, 4, 3, 4, 2}`

then the frequency of element “2” is 3, frequency of element “3” is 2 and frequency of element “4” is 2.

## Java Program to find the frequency of each element in the array

In the following example, we have an array `numbers`

. In this array there are elements that reappeared again and we need to **count the frequency of each element**.

We ran a nested for loop(loop inside loop), in such a way that the each element of an array is compared to the all the elements of the same array, and every time there is a match, we increase the value of the `count`

variable that counts the frequency.

Since, elements appeared multiple times, we need to avoid counting the frequency of same element again. For this, we have assigned a -1 value to the already counted elements using `counted`

variable.

In the end, elements and their frequency in the array is displayed, here also we are using the `counted`

variable to avoid printing the frequency of same element again.

public class JavaExample { public static void main(String[] args) { //Initializing an array int [] numbers = new int [] {2, 2, 3, 4, 5, 5, 5, 3, 2, 4}; //This array will store the frequency of each element int [] frequency = new int [numbers.length]; int counted = -1; for(int i = 0; i < numbers.length; i++){ int count = 1; for(int j = i+1; j < numbers.length; j++){ if(numbers[i] == numbers[j]){ count++; //To avoid counting the frequency of same element again frequency[j] = counted; } } if(frequency[i] != counted) frequency[i] = count; } //Printing the frequency of each element for(int i = 0; i < frequency.length; i++){ if(frequency[i] != counted) System.out.println("Element: "+numbers[i] + " Frequency: " + frequency[i]); } }}

**Output:**

Element: 2 Frequency: 3 Element: 3 Frequency: 2 Element: 4 Frequency: 2 Element: 5 Frequency: 3