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Java Math.exp() Method

By Chaitanya Singh | Filed Under: java

Java Math.exp() method returns e raised to the power of given argument. Here e is a Euler’s number, whose approximate value is 2.718281828459045.

public class JavaExample
{
  public static void main(String[] args)
  {
    double num = 1;
    // returns e (approx. 2.718281828459045) to power of 1
    System.out.println(Math.exp(num));
  }
}

Output:

2.718281828459045

Syntax of Math.exp() method

Math.exp(2); //returns 7.38905609893065

exp() Description

public static double exp(double num): Returns e raised to the power a double argument num.

exp() Parameters

  • num: Exponent double value. Passed as an argument to the method.

exp() Return Value

  • Returns enum.
  • If the argument is NaN (Not a number), then it returns NaN.
  • If the argument is positive infinity, then it returns positive infinity.
  • If the argument is negative infinity, then it returns positive zero.

Example 1

public class JavaExample
{
  public static void main(String[] args)
  {
    double num = 10, num2 = 2;
    System.out.println(Math.exp(num));
    System.out.println(Math.exp(num2));
  }
}

Output:

Java Math.exp() Example Output_1

Example 2

public class JavaExample
{
  public static void main(String[] args)
  {
    double num = -10, num2 = 0;
    System.out.println("exponent is a -ve number: "+Math.exp(num));
    System.out.println("exponent is zero: "+Math.exp(num2));
  }
}

Output:

Java Math.exp() Example Output_2

Example 3

public class JavaExample
{
  public static void main(String[] args)
  {
    double num = 0.0/0, num2 = 4.0/0;
    System.out.println("exponent is NaN: "+Math.exp(num));
    System.out.println("exponent is +ve Infinity: "+Math.exp(num2));
  }
}

Output:

Java Math.exp() Example Output_3

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❮ Java Math

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